hollow diamond using for loop c++ code user enter input size of diamond

hollow diamond using for loop c++ code user enter input size of diamond
Di Posting Oleh : Simple Learning
Kategori : diamond for hollow input loop size user using

write a c++ program which takes size of diamond and display hollow diamond using nested for loop and asterisk character.
Output should be look like bellow

 User can enter its desired size of diamond either even or odd

For Example
If user enters size of 3
3 lines of will be formed above middle and 3 lines will be formed below middle line

Concept used:

• Nested for loop
• if statement

c++ code:

#include<iostream> using namespace std; int main() { cout<<"Enter size of  Daimond:  ";     int size;   cin>>size;     int z=1;   for ( int i=0; i<=size; i++)   {     for (int j=size; j>i; j--)     {       cout<<" "; // printing space here     }     cout<<"*";  // printing asterisk here     if ( i>0)     {       for ( int k=1; k<=z; k++)       {         cout<<" ";       }       z+=2;       cout<<"*";     }     cout<<endl; // end line similar  to \n   }   z-=4;   for (int i=0; i<=size-1; i++)   {     for (int j=0; j<=i; j++)     {       cout<<" ";     }     cout<<"*";     for (int k=1; k<=z; k++)     {       cout<<" ";     }     z-=2;     if (i!=size-1)     {       cout<<"*";     }     cout<<endl;   } return 0; }

If user enter size equal to 10

Recommended: Dry run the code line by line it will help to understand quickly and also clear the working of nested for loop.

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